kingdede7667 kingdede7667
  • 04-08-2018
  • Mathematics
contestada

Find the polar equation for the cartesian curve x^2-y^2 = sqrt(x^2+y^2)

Respuesta :

valetta valetta
  • 04-08-2018

ANSWER:

r = [tex] \frac{1}{cos2(theta)} [/tex]

Explaination:

Convert the given curve into the the polar form.

x = rcosθ

y = rsinθ

in f(x,y) = (x²-y²) - √(x²+y²) = 0

put the values of x & y in given curve equation.

We get at,

g(r,θ) = (r²cos²θ - r²sin²θ) - √(r²cos²θ + r²sin²θ) = 0

g(r,θ) = r²(cos²θ - sin²θ) - √r² = 0

We know that,

cos²θ - sin²θ = cos2θ

g(r,θ) = r²(cos2θ) - r = 0

Solve for r

Finally we get:

r = [tex] \frac{1}{cos2(theta)} [/tex]

Ver imagen valetta
Answer Link

Otras preguntas

Solve for x. Answer in Interval Notation using Grouping Symbols. x^2+9x<36
How much would $200 invested at 4% interest compounded every 6 months be worth after 5 years?
A car traveling on a street stopped 30 meters after the brakes were applied. About how fast was the car traveling?
Two rectangles are similar. One has a length of 11 cm and a width of 10 cm, and the other has a width of 7 cm. Find the length of the second triangle. Round to
What symbol replaces the and < ,>,= 9/1 and 8/10
A circular pin has a diameter of 6.2 centimeters. Which is closest to the area of the pin? Use 3.14 for
Find the slope and y-intercept of the line 18x+4y=112
a 12 foot ladder is leaning against a building. the ladder makes a 45 degree angle with the building. how far up the building does the ladder reach
help please thank you
ples help will give brainlist deatils in the image