corinam9851 corinam9851

02-04-2019
Chemistry

contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05

m2=0.015 and

v2=25.00mL

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

= 7.50 mL

Answer Link

Otras preguntas

Device management is the process of managing (???????) devices

2 dived by 440 eplain please

the government of india has,since independence ,taken several steps to put an end to casteism in india. do you think that discrimination on the basis of caste n

Carbohydrates are converted to energy by the process of hydrolysis. true or false

Which strategy is LEAST helpful when organizing sequences of ideas in a project? (Points : 1) Keeping readers needs and limits in mind Repeatedly covering known

A history of a person's life told by another person is known as a(n): A. Auto-Biography B. Biography C. Non-Fictional Biography D. Fictional Biography

What is the degree of comparison for the underlined adjective in the sentence? Can you believe the height of that tall sequoia tree? A. positive B. comparati

What country claims Miguel Hidalgo as a revolutionary hero?

write a short story about a time when you had to overcome the force of gravity to get something done

During working hours an electrician should not wear a. shoes with rubber-type soles and heals. b. a wristwatch or ring. c. a long sleeve shirt. d. a Class B