hayleee8223 hayleee8223
  • 12-04-2019
  • Physics
contestada

1. Calculate the force between charges of 0.000569 C and 0.00000186 C, if they are 0.5 m apart.

Respuesta :

skyluke89
skyluke89 skyluke89
  • 21-04-2019

Answer:

38.1 N

Explanation:

The electrostatic force between two charged objects is given by:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two objects

In this problem, we have

[tex]q_1 = 0.000569 C\\q_2 = 0.00000186 C\\r = 0.5 m[/tex]

so, the electrostatic force is

[tex]F=(9\cdot 10^9 Nm^2 C^{-2})\frac{(0.000569 C)(0.00000186 C)}{(0.5 m)^2}=38.1 N[/tex]

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