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02-05-2016
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Solve ax2 + bx +c = 0 when a=5, b = -23 and c = 12 to find the zeros (x intercepts)

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konrad509 konrad509

02-05-2016

[tex]5x^2-23x+12=0\\ 5x^2-20x-3x+12=0\\ 5x(x-4)-3(x-4)=0\\ (5x-3)(x-4)=0\\ x=\dfrac{3}{5} \vee x=4 [/tex]

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