YunoMatashi1029
YunoMatashi1029 YunoMatashi1029
  • 04-07-2019
  • Mathematics
contestada

The problem is in the pictures, please show step by step how to do it. Thanks! :)

The problem is in the pictures please show step by step how to do it Thanks class=

Respuesta :

sumjok
sumjok sumjok
  • 04-07-2019

Answer:

-4,-5/2

Step-by-step explanation:

2x^2+3x-20 =0

2x^2+8x-5x-20 =0

2x(x+4)-5(x+4) =0

(x+4)(2x-5) =0

Either,

x+4=0

x=-4

Or,

2x-5=0

2x=5

x=5/2

Answer Link
konrad509
konrad509 konrad509
  • 04-07-2019

[tex]2x^2+3x-20=0\\2x^2+8x-5x-20=0\\2x(x+4)-5(x+4)=0\\(2x-5)(x+4)=0\\x=\dfrac{5}{2} \vee x=-4[/tex]

Answer Link

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