Respuesta :
Answer:
C. Both Carter and Demi are correct and would get the same answer.
Step-by-step explanation:
Here, the given polynomial is : [tex]P(x) =6x^2 + 4x + 3 [/tex]
The given monomial : [tex]Q(x) Â = 2 x[/tex]
Now, according to the given question:
Dividend = P(x), Divisor  = Q(x)
Now, Carter divide P(x) by Q (x) with LONG DIVISION METHOD.
If we divide P(x) by Q(x) by Long division, we get:
[tex]\frac{P(x)}{Q(x)} Â = \frac{(6x^2 + 4x + 3)}{(2x)} Â = 3x + Â 2 + \frac{3}{2} x = R(x)[/tex]
Also, if Demi divides each term of P(x) by The given monomial (2x) , we get:
[tex]\frac{P(x)}{Q(x)} Â = \frac{(6x^2 + 4x + 3)}{(2x)} Â = \frac{6x^2}{2x} Â + \frac{4x}{2x} +\frac{3}{2x} \\= 3x + Â 2 + \frac{3}{2} Â = R(x)[/tex]
⇒In both the case, R(X)Quotient is SAME.
Hence, Both Carter and Demi are correct and would get the same answer.
Answer:
Both Carter and Demi are correct and would get the same answer.
Step-by-step explanation: