corbinholifielovjwjz
corbinholifielovjwjz corbinholifielovjwjz
  • 03-04-2020
  • Chemistry
contestada

How much of NaCl is in 1.90 L of 0.300 M
NaCl?
Answer in units of mol.

Respuesta :

joseaaronlara
joseaaronlara joseaaronlara
  • 03-04-2020

Answer:

The answer to your question is 0.57 moles

Explanation:

Data

volume = 1.9 L

[NaCl] = 0.3

moles of NaCl = ?

Process

1.- To solve this problem use the formula of Molarity.

Molarity = moles/ volume (l)

-Solve for moles

moles = Molarity x volume

-Substitution

 moles = 0.3 x 1.9

-Result

 moles = 0.57

-Conclusion

There are 0.57 moles of NaCl in 1.90 L of a 0.3 M solution.

Answer Link

Otras preguntas

Which of the following statements is true? a. Money is a medium of exchange. c. Money serves as a store of value. b. Money is a unit of account. d. all of the a
how to write 70000 written in word form
Can you explain how to use the combine place values strategy to find 223-119
which substance cannot be broken down by a chemical change? 1) ammonia 2) ethanol 3) propanol 4) zirconium
Word problems with rational numbers
When on November 11th, 1918, an armistice was signed to end World War I, the war's biggest losers were _____ because their governments ceased to exist. a. the
True or false? Four eighths is equal to five twelves?
I Am A Number That Is Double The Product Of 2 And 7. One Of My Factors Is 7 What Is My Other factor
change 12.39% to a decimal
Which statement about novels is true? A.They use dramatic elements to depict the flaws of human nature in a succinct, poignant way. B.They use poetic techniques