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A steel aircraft carrier is 371 m long when moving through the icy North Atlantic at a temperature of 2.5° C. By how much does the carrier lengthen when it is traveling in the warm Mediterranean Sea at a temperature of 20° C?

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Answer:

The carrier lengthen by 7.79 × 10⁻ÂČ m when it is traveling in the warm Mediterranean Sea at a temperature of 20° C

Explanation:

The initial length of steel ([tex]L_0[/tex]) = 371 m

The change in length = ΔL

The change in temperature (ΔT) = 20°C - 2.5°C = 17.5°C

The coefficient of linear expansion of steel (α) = 12 × 10⁻⁶ ⁰C⁻Âč

ΔL = αL₀ΔT = 371 × 17.5 ×  12 × 10⁻⁶ = 7.79 × 10⁻ÂČ m

The carrier lengthen by 7.79 × 10⁻ÂČ m when it is traveling in the warm Mediterranean Sea at a temperature of 20° C

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