Nicholascorea29 Nicholascorea29
  • 13-05-2020
  • Mathematics
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2x^2-3x=2x-2 solved by factoring

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baabaagreysheep
baabaagreysheep baabaagreysheep
  • 13-05-2020

Your answer is x = 1/2 and x = 2.

First we need to rearrange the equation so that it equals 0:

2x² - 3x = 2x - 2

2x² - 5x + 2 = 0

Then to factorise, we know that the x terms in the brackets will be 2x and x, so then you just need to deduce that you will need (2x - 1) and (x - 2) to get -5x + 2 at the end of the expression:

(2x - 1)(x - 2) = 0

Then we set each bracket equal to 0 and solve for x:

x = 1/2, x = 2

I hope this helps! Let me know if you have any questions :)

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