Answer:
The  value is  [tex]q =  70.8\ C[/tex]
Explanation:
From the question we are told that
  The  area is  [tex]A =  2.0 \ k m^2 = 2000000 \  m[/tex]
  The height is  [tex]h  =  10 \  km  =  10000 \  m[/tex]
  The  electric field is  [tex]E =  4.0*10^{6} \  N/C[/tex]
Generally the electric field is mathematically represented as
   [tex]E =  \frac{q}{A *  \epsilon_o }[/tex]
Here [tex]\epsilon_o }[/tex] is the permitivity of free space with value Â
   [tex]\epsilon_o }  =  8.85 *10^{-12} \  N \ m^2 /C^2[/tex]
=> Â [tex]4.0*10^{6} = Â \frac{q}{2000000 * Â Â 8.85 *10^{-12} }[/tex]
=> [tex]q = Â 70.8\ C[/tex]