Given:
The charges;
q₁=-0.02 C
q₂=0.03 C
The separation between the charges, r=2.4 m
To find:
The electric force between the charges.
Explanation:
From Coulomb's law,
[tex]F=\frac{k|q_1||q_2|}{r^2}[/tex]Where k is the Coulomb's constant.
On substituting the known values,
[tex]\begin{gathered} F=\frac{9\times10^9\times0.02\times0.03}{2.4^2} \\ =937.5\times10^3\text{ N} \\ =937.5\text{ kN} \end{gathered}[/tex]Final answer:
The electric force between the charges is 937.5 kN.
