YaniraJ402260 YaniraJ402260
  • 03-11-2022
  • Mathematics
contestada

Solve the equation 42+7c - 5 = 0 using the quadratic formula

Solve the equation 427c 5 0 using the quadratic formula class=

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KevontaeS745646 KevontaeS745646
  • 03-11-2022

The equation is:

[tex]4c^2+7c-5=0[/tex]

so we can use the cuadratic equation so:

[tex]\begin{gathered} c=\frac{-b\pm\sqrt[]{b^2-4(a)(c^{\prime})}}{2(a)} \\ \text{where} \\ a=4 \\ b=7 \\ c^{\prime}=-5 \end{gathered}[/tex]

So if we replace in the equation we will have:

[tex]c=\frac{-7\pm\sqrt[]{7^2-4(4)(-5)}}{2(4)}[/tex]

So we simplify to solve the problem so:

[tex]c=\frac{-7\pm\sqrt[]{129}}{8}[/tex]

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