lyrictjackson lyrictjackson
  • 03-06-2018
  • Mathematics
contestada

What is the true solution?

ln e^(ln x)+ln e^(ln x^2)=2 ln 8

Respuesta :

LammettHash
LammettHash LammettHash
  • 03-06-2018
Assuming [tex]x[/tex] is real:

[tex]\ln e^{\ln x} = \ln x\cdot\ln e=\ln x[/tex]

[tex]\ln e^{\ln x^2} = \ln x^2\cdot\ln e = \ln x^2 = 2\ln x[/tex]


So

[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\iff\ln x+2\ln x=3\ln x=2\ln 8[/tex]

[tex]\implies\ln x=\dfrac23\ln 8=\ln 8^{2/3}[/tex]

[tex]\implies x=e^{\ln 8^{2/3}}=8^{2/3}=(8^2)^{1/3}=64^{1/3}=4[/tex]
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brekv
brekv brekv
  • 14-04-2020

Answer:

It is 4 or B

Step-by-step explanation:

I took the test

Answer Link

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