At s.t.p, the volume of a gas =22.4dm³ Talking the problem, At 1atm, 273K the volume =7 moles *22.4dm³/mol At 323K, 2.90atm, volume =? The combined gas equation P1v1/T1=P2v2/T2 P1=1atm P2=2.9atm T1=273K T2=323K V1=156.8dm³ Therefore, 1*156.8dm³/273=2.9atm*V2/323 V2=(156.8dm³*323K)/(273K*2.9atm) = 64dm³
