proutyhaylee
proutyhaylee proutyhaylee
  • 04-02-2019
  • Mathematics
contestada

Solve 2^x=32 and rewrite this equation in a logarithmic form

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 04-02-2019

Answer:

x=5

x = log2(32)

Step-by-step explanation:

2^x=32

Rewrite 32 as 2^5

2^x = 2^5

Since the bases are the same, the exponents have to be the same

x=5

2^x=32

Take log base 2 on each side

log2(2^x) = log2(32)

x = log2(32)

Answer Link

Otras preguntas

What decimal is written in words "forty-six and seven thousandths"?
About how much pressure do the feet of a 6000 kg elephant exert on the ground assuming each foot has an area of 0.10 square meter
The variable, n, represents a number that a spectator chooses. what is the result after the calculation of 2n + 4 – n – 4?
What is 1/20 - 1/36? Keep it in fraction form.
How did the peace made after world war 2 differ from world war 1?
What consequences do we face if we do not take responsibility for our actions?
How long does it take to get a doctorate in math education?
What happens to tsunamis as they move toward shore?
What figure has one endpoint and continues forever in one direction?
Solve for x. 3x - 4 = 2x - 10