seng8320 seng8320
  • 02-05-2020
  • Mathematics
contestada

What are the vertical asymptote(s) and hole(s) for the graph of y= x-1 over X squared + 6x+ 8

Respuesta :

slinl slinl
  • 02-05-2020

Answer:

You have vertical asymptotes on x=-4,-2

Step-by-step explanation:

This question is very simple. Since you have a denominator all you need to do is factor the bottom and find the zeros. When you factor the bottom of the equation you should get (x+4)(x+2). Now you have to set the bottom equal to zero to find the zeros. This means (x+4)=0 and (x+2)=0 So you get two answers x=-4 and x=-2 Therefore your two vertical asymptotes are on x-4,-2

Answer Link

Otras preguntas

find the area and perimeter of an isosceles trapezoid with legs 25cm and bases 16cm and 30cm
what is the plural of volcano
the three groups of invaders were?
How Do You Do: 2(n-7)+3=9 And: 4h+7h-16=6
Abolished indentured servitude and slavery in the United States
what are the benefits of genetic variation?
England and Canada have what cultural characteristic in common?A. A majority of the population in both is Roman Catholic.B A majority of the population in both
What phrase does Winston repeatedly write in his diary while unaware that he is writing it? Down with Big Brother Long live the Brotherhood! The proles are the
derivative of this function Y= -7X³ -8X² +6X +3
A substance with ph of 6 is called? A. acid b. a base. c. water. d. a suspension