Answer:
[tex]n_{NaOH}=40molNaOH[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction should be:
[tex]2NaOH+CO_2\rightarrow Na_2CO_3+H_2O[/tex]
In such a way, if 20 moles of carbon dioxide react with sodium hydroxide, the equivalent moles, considering their 1:2 molar ratio at the chemical reaction, result:
[tex]n_{NaOH}=20molCO_2*\frac{2molNaOH}{1molCO_2}\\ \\n_{NaOH}=40molNaOH[/tex]
Best regards.
