LianaL380159 LianaL380159
  • 03-11-2022
  • Mathematics
contestada

solve the volume of a cone, V=1/3πr^2h, for h.h = ?basically like v=lwh, for h. and h = v over lw (v/lw)

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MariellU601059 MariellU601059
  • 03-11-2022
[tex]\begin{gathered} V=\frac{1}{3}r^2h\pi \\ \text{Solving for h:} \\ \text{Multiply both sides by 3:} \\ 3V=3\cdot\frac{1}{3}r^2h\pi \\ 3V=r^2h\pi \\ \text{Divide both sides by }r^2\pi \\ \frac{3V}{r^2\pi}=\frac{r^2h\pi}{r^2\pi} \\ \frac{3V}{r^2\pi}=h \\ \\ h=\frac{3V}{r^2\pi} \end{gathered}[/tex]

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