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  • 03-01-2018
  • Mathematics
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X^2+(y-5)=25 find the center of the circle

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mathildaramaqap1ywpc
mathildaramaqap1ywpc mathildaramaqap1ywpc
  • 03-01-2018

[tex] {x}^{2} + (y - 5) = 25 \\ {x }^{2} + y = 25 + 5 \\ {x}^{2} + y = 30 \\ {x}^{2} + y = \sqrt{30} \\ [/tex]
centre: (0,0)
Radius: square root of 30
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